进程同步,哲学家进餐共享临界区变量.定义信号量机制控制进程不互斥!-process synchronization, philosopher dining area share critical variables. Definition signal to the process control mechanism not contradict! 下载
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操作系统课程信号量机制实验（哲学家吃乳猪），JAVA源码, 下载
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ucos 实现任务创建，信号量机制的实现 实现理发师问题的模拟-OUT achieving task creation, the volume signal mechanism to achieve the realization of the simulation Seville 下载
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自己写的。用信号量机制来解决哲学家问题中的死锁。附有详细注解。-wrote it myself. Using signal volume philosopher mechanism to solve the problem of deadlock. Accompanied by a detailed explanation. 下载
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在Linux环境下，用C语言和信号量机制实现了五个哲学家进餐的互斥关系-the Linux environment, the C language and signal mechanism to achieve the volume of five philosophers dining mutex relations 下载
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经典进程同步和互斥另类WINDOWS解法.定义信号量机制在WINDOWS下完成哲学家进餐问题.-classical process synchronization and mutex WINDOWS alternative solution. Volume definition signal mechanism in Windows complete the dining philosophers problem. 下载
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奇偶哲学家通过信号量机制控制进程的同步和互斥访问临街区域,保证正常执行!-signal through the volume control mechanism for the process of synchronization and mutex visit to the region along the street to ensure normal execution! 下载
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一个windows进程互斥访问的程序，用到信号量等机制，采用时间片轮转法！ -a visit to contradict the procedure used signal to other mechanisms, using time-rotate Act! 下载
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系统的同步机构采用信号量上的p、v操作的机制；控制机构包括阻塞和唤醒操作；时间片中断处理程序处理模拟的时间片中断；进程调度程序负责为各进程分配处理机。系统设计3个并发进程，它们之间有如下同步关系：3个进程需要互斥使用临界资源s2,进程1和进程2又需要互斥使用临界资源s1。系统在运行过程中随即打印各进程的状态变换过程，系统的调度过程及公共变量的变化情况。-system synchronization signal used agencies on the volume of p, v operation of the mechanism; Control agencies, including obstruction and awaken operation; Time Slice interrupt handling procedures-time simulation of interruption; The process scheduler is responsible for the allocation process processor. System design three concurrent process, and they are as follows synchronization : three processes require the use of critical resources contradict s2, a process and the need to process two mutually exclusive use of critical resources s1. System in the course of operation of the printing process was the transformation process of the state, the activation process variables and the public of the changes. 下载
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试验目的：通过研究Linux的线程机制和信号量实现生产者消费者问题的并发控制 说明：有界缓冲区内设有20个存储单元，放入/取出的数据项设定为1~20这20个整型数。 要求： (1)每个生产者和消费者对有界缓冲区进行操作后，即时显示有界缓冲区的全部内容.当前指针位置和生产者/消费者线程的标识符 (2)生产者和消费者各有两个以上 (3)多个生产者或多个消费者之间须共享对缓冲区进行操作的函数代码。-Test Objective : To study the Linux threading mechanism and signal to producers and consumers to achieve the concurrency control : a boundary buffer There are 20 storage units, Add / remove data items for a set of 20 ~ 20-integer. Requirements : (1) Each producer and consumer sector of the buffer zone is operated, immediately after the sector showed a buffer in its entirety. The current position and producer / consumer threads identifier (2) producers and consumers have two or more (3) A number of producers or many consumers to be shared between the right to operate the buffer function code. 下载
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